Wizzer's Blog

查询1公里范围内的经纬度数据：

select 6371.012 *
       acos(cos(acos(-1) / 180 * d.LATITUDE) *
            cos(acos(-1) / 180 * 31.885972440801) *
            cos(acos(-1) / 180 * d.LONGITUDE - acos(-1) / 180 * 117.30923429642) +
            sin(acos(-1) / 180 * d.LATITUDE) *
            sin(acos(-1) / 180 * 31.885972440801))*1 as a,
       id,name 
  from loc_data d
 where 6371.012 *
       acos(cos(acos(-1) / 180 * d.LATITUDE) *
            cos(acos(-1) / 180 * 31.885972440801) *
            cos(acos(-1) / 180 * d.LONGITUDE - acos(-1) / 180 * 117.30923429642) +
            sin(acos(-1) / 180 * d.LATITUDE) *
            sin(acos(-1) / 180 * 31.885972440801))*1 < 1 order by a asc